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Old 09-08-2006, 01:42 AM   #51
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youre not alone, bro...i always kinda guesstimate the bottom...itd be kool if there was a super understandable way to read it.
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Old 09-08-2006, 01:44 AM   #52
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ok but what does it actually mean how do u even guess im completely confuessed on that part i have no clue how to figure out about what rpm it will be at or what the bottom actually means
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Old 09-08-2006, 07:34 AM   #53
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Its some formula that calculates what Airflow is what RPM or something like that. Hopefully someone can jump in here with the formula and explain it a lil
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Old 09-08-2006, 12:53 PM   #54
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Here is what the equation on the bottom means.
w = air flow, in pounds mass of air per minute. this is uncorrected for atmospheric pressure and temperature. Any change in the local temperature or pressure will change the actual performance of the compressor.

The quantity under the radical are temperature correction. 519 is a standard correction term, but we'll use 545 to be consistent with the map.
T1c = local temperature, expressed in degrees Rankine. To convert degrees Fahrenheit, deg R = deg F + 459

The quantity in the denominator is the local pressure correction.
P1c = local atmospheric pressure, expressed in psia. Like I said, I think the 28.4 is a typo, but i could be wrong. Normal pressure corrections have 14.7psia; i am not sure why 28.4 is there. We'll use the 28.4 to be consistent with the map.

edit: found out the 28.4 is actually the measurement for standard (or close to) pressure measured in inches of mercury. I should have known that. We'll use 14.7 instead of the 28.4.

Here is an example:
The local temperature is 65 degrees fahrenheit, and the local pressure is a little low, say 14.5 psia. We want to run at 8psi on the street, and want to see how much flow that will be pushing. We will be needing the pressure ratio to read the vertical axis, so adding 8 psig (boost) to 14.5 psia(atmospheric pressure), and divide by the 14.5 psia. (8+14.5)/14.5 = 1.55.
We'll be using a T3 super 60 turbo
According to the map, within the best efficiency island, at a pressure ratio of 1.55, corrected flow will be anywhere from about 12 to 17 lbm/min, eyeballing the map. To give to an idea of what the uncorrected flow will be, the temperature correction factor will be sqrt((65+459)/545) = .98
The pressure correction factor will be 14.5/14.7 = .986


12lbm/min corrected will be 12*.98/.986 = 11.99 lbm/min actual.
17lbm/min corrected will be 17*.98/.986 = 16.98 lbm/min actual.

You can see that at near standard conditions, the actual and corrected values will be similar. If you're are living in arizona however, and the local temperature is 110 degrees F, and 14.5psi, you'll be seeing actual flow numbers from 12.4 to 17.6 lbm, a 3.5% difference. Not a big difference, but a 3% difference can mean the difference between a safe engine and a broken engine if you are tuning aggressively. Again, this is just one application.
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Old 09-08-2006, 01:22 PM   #55
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Thank you, thank you Coming in again with more GREAT info!!
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Old 09-11-2006, 12:58 AM   #56
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Thanks, you always supply me with great information that alwayz helps.... but how do u know the air flow for your particular application... heres and example... running a GT35R in colorado springs pushing 19 lbs.... i dont know how to figure it for ur car i now know how to figure out the corrected values and the range that ir would run best in... i know that the pressure ratio would be about 2.3 but how would you get your car to be able to have 40lbs/min to be in the best effiecientcy island?... i might be thinking about this in the worng way but please help

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Old 09-13-2006, 01:18 AM   #57
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someone should reply b/c im not sure how to find out how much air flow your car would put out... do you use an equation or do you have to have your car dynoed....
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