# For All Of U Who Are Good At Math..

Discussion in 'Members' Lounge' started by 22crazy, May 4, 2003.

1. ### 22crazySenior Member

Messages:
307
0
Joined:
Nov 13, 2002
whats up. i have a question that been pissing me off and i was wondering if any of you could solve it. the question: if you construct equalateral triangles of the sides of a quaderlateral, alternately inward and outward, when you connect the vertex of each triangle, the result is a parallelogram. Prove it (the parallelogram that is formed). ill see if i can make the picture.

Messages:
307
0
Joined:
Nov 13, 2002
3. ### BigJI'm just about that action Boss.VIP

Messages:
11,118
419
Joined:
Oct 4, 2002
Location:
Washington
Yeah looks to me like some seriously hard proof that must be written to prove that one. I am just in mathanalysis in sophomore year of high school so I am little under that problem for now.

4. ### vpSPOONsolSenior Member

Messages:
304
0
Joined:
Apr 1, 2003
Location:
mildenhall village, england
well simply u just take the second derivative of the intergral of A to B, assuming that the distance from A to C is equal.... u then muliply that by the sides of the parrallogram, which gives u = j/p... im taking calculus for my senior year right now, and i dont have ur answer.
im sure some of the older college grad guys can answer that though...

5. ### BakerSenior Member

Messages:
754
0
Joined:
Oct 9, 2002
Location:
Schaumburg, IL
I could probably do it but the resulting headache would not make it worthwhile

6. ### 22crazySenior Member

Messages:
307
0
Joined:
Nov 13, 2002
well can anyone help me, its been bugging me alot and i need to complete it. thanx for the help though. i no it has to do something with the 60 degrees in the equalateral triangles and also, u have to construct a parallelogram within the quaderlateral: that is done by connecting the midpoints.

7. ### BodyDroppedNikes...PENDEJO....VIP

Messages:
10,593
103
Joined:
Sep 28, 2002
Location:
caught in a mosh...
<--this is me after reading this topic

8. ### DazedCivic99Senior Member

Messages:
667
0
Joined:
Sep 29, 2002
Location:
Florida
is this supposed to be a 3D object?
If it is i sorta see what you are going for but a little lost at the moment

as for the calculas answer vpspoon you just reminded me that i need to study for my AP calculas test, damn you j/k

9. ### 22crazySenior Member

Messages:
307
0
Joined:
Nov 13, 2002
no its a 2D object...can anyone still help me

10. ### pills_PMDSuper Moderator

Messages:
4,232
0
Joined:
Sep 30, 2002
Location:
New Albany, OH
what math class is it for?
there are probably several ways of doing it..

and which part am i suposed to prove.. that the red lines are a parallelogra?M

11. ### pissedoffsolRETIRED

Messages:
49,693
54
Joined:
Sep 28, 2002
Location:
Retirement Home
Calesta, i think this ones for you man

12. ### CRX-YEMSuper ModeratorModeratorVIP

Messages:
4,625
56
Joined:
Sep 29, 2002
Location:
Wallingford, CT
man I can't remember the last time I did a geometric proof. I'd have to bust out my books, but I've got finals this week so that ain't happening.

13. ### doofnoilSenior Member

Messages:
197
0
Joined:
Nov 10, 2002
If you just have to prove that a parallelogram would exist, I would look at the relation between the sides of the quad. and the parallel. to see if they correspond ?

14. ### lsvtecGNU/Linux Evangelist

Messages:
5,453
4
Joined:
Sep 30, 2002
Location:
Greater Portland, OR

You need to prove that Angles 1 & 6 are equal, and anges 3 & 4 are equal. This proves that angles 2&5 are equal because the sums of 1, 2, & 3 and 4, 5, & 6 are both 60 degrees. Then all you have to do is prove that each pair of opposing sides are equal length. Then you have a parallelogram.

15. ### dohcvtec_accordWRX Sellout

Messages:
8,433
1
Joined:
Sep 29, 2002
Location:
The left lane
I was wondering how long it would take you to get involved Eric.

16. ### lsvtecGNU/Linux Evangelist

Messages:
5,453
4
Joined:
Sep 30, 2002
Location:
Greater Portland, OR
I had to sit and think for a while. It has been forever since I did a Geometric proof. And even then (freshman year of HS) I wasn't very good at them.

You could also simply prove that the opposite inside angles of the parallelogram are equal instead of showing the opposite sides equal.

17. ### dohcvtec_accordWRX Sellout

Messages:
8,433
1
Joined:
Sep 29, 2002
Location:
The left lane

Exactly what I was going to say.

*pushes non-existent glasses up on nose, goes for high-five with lsvtec, misses horribly, gives nerdy, snorty laugh*

18. ### 22crazySenior Member

Messages:
307
0
Joined:
Nov 13, 2002
actually those angles 4 3 and 1 6 are not equal, but yet 5 and 2 are....i was able to prove it using geometer sketch pad, but i dont no how to do it paper and pencil method

19. ### Gen2TegSenior Member

Messages:
554
0
Joined:
Jan 2, 2003
Location:
san francisco
i didn't even read the question, i just looked at the picture and it made my head hurt

Messages:
5,453